Given: r || s and q is a transversal Prove: ā 4 is supplementary to ā 6 Given that r || s and q is a transversal, we know that ā 3 ā
ā 6 by the . Therefore, mā 3 = mā 6 by the definition of congruent. We also know that, by definition, ā 4 and ā 3 are a linear pair, so they are supplementary by the linear pair postulate. By the definition of supplementary angles, mā 4 + mā 3 = 180°. Using substitution, we can replace mā 3 with mā 6 to get mā 4 + mā 6 = 180°. Therefore, by the definition of supplementary angles, ā 4 is supplementary to ā 6.