elizabethtapp6720 elizabethtapp6720

01-02-2020
Mathematics

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A gravel path is to be built around an 12 ft by 22 ft rectangular garden. If the width remains constant, how wide can the path be if there is enough gravel for 552 square feet?

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beingteenowfmao beingteenowfmao

01-02-2020

Answer:

2w(12+2w)+2*22w = 552

w(12+2w)+22w = 276

2w^2+34w-276 = 0

w^2+17w-138 = 0

(w-6)(w+23) = 0

width = 6 ft

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