Respuesta :
Answer:
Ā Ā Ā Iā = 143.79
Explanation:
To solve this problem, work them in two parts. A first one where we look for the intensity of the incident light in the set and a second one where we silence the light transmuted by the other set,
Let's start with the set of three curling irons
Beautiful light falls on the first polarized is not polarized, therefore only half the radiation passes
Ā Ā Ā Ā Ā Ā Ā Iā = Iā / 2
this light reaches the second polarized and must comply with the Mule law
Ā Ā Ā Ā Ā Ā Ā Iā = Iā cosĀ² tea
The angle between the first polarized and the second is Tea = 29.0Āŗ
Ā Ā Ā Ā Ā Ā Ā Iā = I / 2 cosĀ² 29
The light that comes out of the third polarized is
Ā Ā Ā Ā Ā Ā Ā Iā = Iā cosĀ² tea
the angle between the third - second polarizer is
Ā Ā Ā Ā Ā Ā Ā tea = 58-29
Ā Ā Ā Ā Ā Ā Ā tea = 29th
Ā Ā Ā Ā Ā Ā Ā Ā I3 = (Iā / 2 cosĀ² 29) cosĀ² 29
indicate the output intensity
Ā Ā Ā Ā Ā Ā Ā Ā I3 = 110
we clear
Ā Ā Ā Ā Ā Ā Ā Iā = 2I3 / cos4 29
Ā Ā Ā Ā Ā Ā Ā Iā = 2 110 / cos4 29
Ā Ā Ā Ā Ā Ā Ā Iā = 375.96 W / cmĀ²
Now we have the incident intensity in the new set of three polarizers
back to the for the first polarizer
Ā Ā Ā Ā Ā Ā Ā Ā Ā Iā = Iā / 2
when passing the second polarizer
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā Iā = I1 cosĀ² 29
Ā Ā Ā Ā Ā Ā Ā Ā Ā Ā I2 = IO /2 cosĀ²29
let's calculate
Ā Ā Ā Ā Ā Ā Ā Ā Iā = 375.96 / 2 cosĀ² 29
Ā Ā Ā Ā Ā Ā Ā Ā Iā = 143.79
