kol2
kol2
04-01-2018
Mathematics
contestada
Please help me out.
Respuesta :
jimthompson5910
jimthompson5910
04-01-2018
Answer: 105 degrees
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Explanation:
It turns out that we can add up the minor arcs TU and JV, then divide by 2, to get the measure of angle TSU
angle TSU = ((minor arc TU)+(minor arc JV))/2
17x+3 = ((150)+(11x-6))/2
17x+3 = (150+11x-6)/2
17x+3 = (144+11x)/2
2*(17x+3) = 2*(144+11x)/2 ... multiply both sides by 2
2*(17x)+2*(3) = 144+11x
34x+6 = 144+11x
34x+6-6 = 144+11x-6 ... subtract 6 from both sides
34x = 138+11x
34x-11x = 138+11x-11x ... subtract 11x from both sides
23x = 138
23x/23 = 138/23 ... divide both sides by 23
x = 6
Use x = 6 to find the measure of angle TSU
angle TSU = 17*x + 3
angle TSU = 17*6 + 3 ... replace x with 6
angle TSU = 102 + 3
angle TSU = 105 degrees
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